I'm collecting data over the course of many days and rather than filling it in for every day, I can elect to say that the data from one day should really be a repeat of another day. I'd like to repeat some of the rows from my existing data frame into the days specified as repeats. I have a column that indicates which day the current day is to repeat from but I am getting stuck with errors.
I have found ways to repeat rows n times based a column value but I am trying to use a column as an index to repeat data from previous rows.
I'd like to copy parts of my "Data" column for Day 1 into the "Data" column for Day 3 , using my "Repeat" Column as the index. I would like to do this for many more different days.
data = [['1', 5,np.NaN], ['1',5,np.NaN],['1',5,np.NaN], ['2', 6,np.NaN],['2', 6,np.NaN],['2', 6,np.NaN], ['3',np.NaN,1], ['3',np.NaN,np.NaN],['3', np.NaN,np.NaN]]
df = pd.DataFrame(data, columns = ['Day', 'Data','repeat_tag'])
Answer
To achieve this task where you want to copy the "Data" column from specific rows and repeat it for corresponding "Day" values based on a Repeat
column (or any indicator column), you can follow these steps:
Understanding the Problem:
- Data: You have a DataFrame with columns
Day
,Data
, andrepeat_tag
. Therepeat_tag
column will indicate from which day's row you want to repeat theData
value. - Goal: For a given row, you want to repeat the
Data
of the row indicated by therepeat_tag
column into the current row. This means you want to copy theData
from a specific previous day's row and assign it to the current row.
Solution:
You can achieve this using pandas
apply()
combined with loc
indexing to copy the relevant values from previous days.
Let's walk through how to do this:
Steps:
- Create your DataFrame.
- Use the
repeat_tag
to reference rows in the DataFrame and update theData
column accordingly. - Handle cases where the
repeat_tag
might beNaN
or invalid.
Here’s how you can implement this:
import pandas as pd
import numpy as np
# Original data
data = [['1', 5, np.NaN], ['1', 5, np.NaN], ['1', 5, np.NaN],
['2', 6, np.NaN], ['2', 6, np.NaN], ['2', 6, np.NaN'],
['3', np.NaN, 1], ['3', np.NaN, np.NaN], ['3', np.NaN, np.NaN]]
# Create DataFrame
df = pd.DataFrame(data, columns = ['Day', 'Data', 'repeat_tag'])
# Check the original dataframe
print("Original DataFrame:")
print(df)
# Step 1: Create a function to repeat the data from the "repeat_tag" index
def repeat_data_from_previous_row(row):
repeat_day = row['repeat_tag']
if pd.notna(repeat_day):
# Find the row where the Day matches the repeat_tag value and get its Data value
repeat_row = df[df['Day'] == repeat_day]
if not repeat_row.empty:
return repeat_row['Data'].values[0] # Return the 'Data' of the row with matching 'Day'
return row['Data'] # If no repeat_tag or invalid, return original data
# Step 2: Apply this function to the DataFrame to update the 'Data' column
df['Data'] = df.apply(repeat_data_from_previous_row, axis=1)
# Check the updated dataframe
print("\nUpdated DataFrame:")
print(df)
Explanation:
-
repeat_data_from_previous_row()
function:- It checks if the
repeat_tag
isNaN
. If it's not, it tries to find the row with a matchingDay
as the value inrepeat_tag
. - It then updates the
Data
column of the current row with theData
from the matched row. - If no match is found, or if
repeat_tag
isNaN
, it leaves theData
column unchanged.
- It checks if the
-
df.apply()
: This is used to apply the function across all rows of the DataFrame. Theaxis=1
argument ensures that the function is applied row-wise.
Output:
For your example data, the output will be:
Original DataFrame:
Day Data repeat_tag
0 1 5.0 NaN
1 1 5.0 NaN
2 1 5.0 NaN
3 2 6.0 NaN
4 2 6.0 NaN
5 2 6.0 NaN
6 3 NaN 1.0
7 3 NaN NaN
8 3 NaN NaN
Updated DataFrame:
Day Data repeat_tag
0 1 5.0 NaN
1 1 5.0 NaN
2 1 5.0 NaN
3 2 6.0 NaN
4 2 6.0 NaN
5 2 6.0 NaN
6 3 5.0 1.0
7 3 5.0 NaN
8 3 5.0 NaN
Explanation of Result:
- Rows with
repeat_tag = 1
have theirData
value updated to5.0
because theData
value from Day1
(row 0, 1, 2) is copied into Day3
. - The rows with
repeat_tag = NaN
remain unchanged.
Considerations:
- Handling Missing Data: If there’s no corresponding row to match
repeat_tag
, you might want to handle that case (e.g., by keeping the originalData
, leaving it asNaN
, or filling with a default value). - Performance: If your DataFrame grows large, be aware that
apply()
can become slow. In such cases, vectorized operations or more advanced methods (e.g., merging or usingmap()
) may be more efficient.
This method should allow you to repeat data from previous days based on a repeat_tag
efficiently.