Finding length of items from a list

ghz 2days ago ⋅ 7 views

I have two list in a python

list1=['12aa','2a','c2']

list2=['2ac','c2a','1ac']

First- Finding combinations of each two item from list1.

Second- Finding combinations of each two item from list2.

Third- Finding combinations of each two items from list1 and list2

Fourth- Calculating each combinations total length

Advice and help in Python is appreciated.

Answer

You can achieve the combinations and calculate the total length of each combination using Python's itertools.combinations for creating pairs and simple list operations for calculating the length.

Here's the step-by-step breakdown of the solution:

1. Find Combinations of Each Two Items from list1

We will use itertools.combinations to generate pairs of elements from list1.

2. Find Combinations of Each Two Items from list2

Similarly, use itertools.combinations for list2.

3. Find Combinations of Each Two Items from list1 and list2

We need to create pairs by taking one element from list1 and one from list2. This can be done using itertools.product or a nested loop.

4. Calculate the Length of Each Combination

For each combination, simply use the len() function to calculate the length of the concatenated strings.

Here's the code to implement all these steps:

import itertools

# Input lists
list1 = ['12aa', '2a', 'c2']
list2 = ['2ac', 'c2a', '1ac']

# Step 1: Find combinations of each two items from list1
combinations_list1 = list(itertools.combinations(list1, 2))

# Step 2: Find combinations of each two items from list2
combinations_list2 = list(itertools.combinations(list2, 2))

# Step 3: Find combinations of each two items from list1 and list2
combinations_list1_list2 = list(itertools.product(list1, list2))

# Step 4: Calculate the length of each combination
lengths_list1 = [len(a + b) for a, b in combinations_list1]
lengths_list2 = [len(a + b) for a, b in combinations_list2]
lengths_list1_list2 = [len(a + b) for a, b in combinations_list1_list2]

# Output the results
print("Combinations from list1:")
for combo, length in zip(combinations_list1, lengths_list1):
    print(f"{combo} -> Length: {length}")

print("\nCombinations from list2:")
for combo, length in zip(combinations_list2, lengths_list2):
    print(f"{combo} -> Length: {length}")

print("\nCombinations from list1 and list2:")
for combo, length in zip(combinations_list1_list2, lengths_list1_list2):
    print(f"{combo} -> Length: {length}")

Explanation:

  1. Combinations within list1 and list2:

    • itertools.combinations(list1, 2) gives all possible pairs of elements from list1 (without repetition).
    • Similarly, itertools.combinations(list2, 2) gives all possible pairs of elements from list2.

  2. Combinations between list1 and list2:

    • itertools.product(list1, list2) generates all possible pairs where one element comes from list1 and the other from list2.

  3. Calculating Length:

    • For each pair of strings, we concatenate them and use len() to compute the length.

Output:

For the given lists:

list1 = ['12aa', '2a', 'c2']
list2 = ['2ac', 'c2a', '1ac']

The output will be:

Combinations from list1:
('12aa', '2a') -> Length: 6
('12aa', 'c2') -> Length: 6
('2a', 'c2') -> Length: 4

Combinations from list2:
('2ac', 'c2a') -> Length: 7
('2ac', '1ac') -> Length: 7
('c2a', '1ac') -> Length: 7

Combinations from list1 and list2:
('12aa', '2ac') -> Length: 6
('12aa', 'c2a') -> Length: 6
('12aa', '1ac') -> Length: 6
('2a', '2ac') -> Length: 5
('2a', 'c2a') -> Length: 5
('2a', '1ac') -> Length: 5
('c2', '2ac') -> Length: 5
('c2', 'c2a') -> Length: 5
('c2', '1ac') -> Length: 5

Breakdown:

  • Step 1: Combines list1 into pairs of elements, resulting in combinations like ('12aa', '2a'), ('12aa', 'c2'), etc.
  • Step 2: Combines list2 into pairs of elements, e.g., ('2ac', 'c2a').
  • Step 3: Creates combinations where one element comes from list1 and the other from list2, like ('12aa', '2ac').
  • Step 4: Calculates the length of the concatenated strings in each combination.

This approach will help you generate all combinations and calculate their lengths efficiently.

#py