jQuery AJAX cross domain

ghz 1years ago ⋅ 2554 views

Question

Here are two pages, test.php and testserver.php.

test.php

<script src="scripts/jq.js" type="text/javascript"></script>
<script>
    $(function() {
        $.ajax({url:"testserver.php",
            success:function() {
                alert("Success");
            },
            error:function() {
                alert("Error");
            },
            dataType:"json",
            type:"get"
        }
    )})
</script>

testserver.php

<?php
$arr = array("element1",
             "element2",
             array("element31","element32"));
$arr['name'] = "response";
echo json_encode($arr);
?>

Now my problem: when both of these files are on the same server (either localhost or web server), it works and alert("Success") is called; If it is on different servers, meaning testserver.php on web server and test.php on localhost, its not working, and alert("Error") is executing. Even if the URL inside AJAX is changed to http://domain.example/path/to/file/testserver.php


Answer

Use JSONP.

jQuery:

$.ajax({
     url:"testserver.php",
     dataType: 'jsonp', // Notice! JSONP <-- P (lowercase)
     success:function(json){
         // do stuff with json (in this case an array)
         alert("Success");
     },
     error:function(){
         alert("Error");
     }      
});

PHP:

<?php
$arr = array("element1","element2",array("element31","element32"));
$arr['name'] = "response";
echo $_GET['callback']."(".json_encode($arr).");";
?>

The echo might be wrong, it's been a while since I've used php. In any case you need to output callbackName('jsonString') notice the quotes. jQuery will pass its own callback name, so you need to get that from the GET params.

And as Stefan Kendall posted, $.getJSON() is a shorthand method, but then you need to append 'callback=?' to the url as GET parameter (yes, value is ?, jQuery replaces this with its own generated callback method).