When should I use a return statement in ES6 arrow functions

ghz 1years ago ⋅ 8878 views

Question

The new [ES6 arrow functions](https://developer.mozilla.org/en- US/docs/Web/JavaScript/Reference/Functions/Arrow_functions) say return is implicit under some circumstances:

The expression is also the implicit return value of that function.

In what cases do I need to use return with ES6 arrow functions?


Answer

Jackson has partially answered this in a similar question:

Implicit return, but only if there is no block.

  • This will result in errors when a one-liner expands to multiple lines and the programmer forgets to add a return.
  • Implicit return is syntactically ambiguous. (name) => {id: name}returns the object {id: name}... right? Wrong. It returns undefined. Those braces are an explicit block. id: is a label.

I would add to this the definition of a [block](https://developer.mozilla.org/en- US/docs/Web/JavaScript/Reference/Statements/block):

A block statement (or compound statement in other languages) is used to group zero or more statements. The block is delimited by a pair of curly brackets.

Examples :

// returns: undefined
// explanation: an empty block with an implicit return
((name) => {})() 

// returns: 'Hi Jess'
// explanation: no block means implicit return
((name) => 'Hi ' + name)('Jess')

// returns: undefined
// explanation: explicit return required inside block, but is missing.
((name) => {'Hi ' + name})('Jess')

// returns: 'Hi Jess'
// explanation: explicit return in block exists
((name) => {return 'Hi ' + name})('Jess') 

// returns: undefined
// explanation: a block containing a single label. No explicit return.
// more: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/label
((name) => {id: name})('Jess') 

// returns: {id: 'Jess'}
// explanation: implicit return of expression ( ) which evaluates to an object
((name) => ({id: name}))('Jess') 

// returns: {id: 'Jess'}
// explanation: explicit return inside block returns object
((name) => {return {id: name}})('Jess')