Question
I have text like:
content = "Do you like to code? How I love to code! I'm always coding."
I'm trying to split it on either a ? or . or !:
content.split(/[?.!]/)
When I print out the results, the punctuation delimiters are missing.
Do you like to code
How I love to code
I'm always coding
How can I keep the punctuation?
Answer
Answer
Use a positive lookbehind regular expression (i.e. ?<=) inside a parenthesis
capture group to keep the delimiter at the end of each string:
content.split(/(?<=[?.!])/)
# Returns an array with:
# ["Do you like to code?", " How I love to code!", " I'm always coding."]
That leaves a white space at the start of the second and third strings. Add a
match for zero or more white spaces (\s*) after the capture group to exclude
it:
content.split(/(?<=[?.!])\s*/)
# Returns an array with:
# ["Do you like to code?", "How I love to code!", "I'm always coding."]
Additional Notes
While it doesn't make sense with your example, the delimiter can be shifted to
the front of the strings starting with the second one. This is done with a
positive lookahead regular expression (i.e. ?=). For the sake of anyone
looking for that technique, here's how to do that:
content.split(/(?=[?.!])/)
# Returns an array with:
# ["Do you like to code", "? How I love to code", "! I'm always coding", "."]
A better example to illustrate the behavior is:
content = "- the - quick brown - fox jumps"
content.split(/(?=-)/)
# Returns an array with:
# ["- the ", "- quick brown ", "- fox jumps"]
Notice that the square bracket capture group wasn't necessary since there is only one delimiter. Also, since the first match happens at the first character it ends up as the first item in the array.
