Sending data from HTML form to a Python script in Flask

ghz 1years ago ⋅ 1392 views

Question

I have the code below in my Python script:

def cmd_wui(argv, path_to_tx):
    """Run a web UI."""
    from flask import Flask, flash, jsonify, render_template, request
    import webbrowser
    app = Flask(__name__)


    @app.route('/tx/index/')
    def index():
        """Load start page where you select your project folder
        or load history projects from local DB."""
        from txclib import get_version
        txc_version = get_version()
        prj = project.Project(path_to_tx)

        # Let's create a resource list from our config file
        res_list = []
        prev_proj = ''
        for idx, res in enumerate(prj.get_resource_list()):
                hostname = prj.get_resource_host(res)
        username, password = prj.getset_host_credentials(hostname)
        return render_template('init.html', txc_version=txc_version, username=username)

Also, I have an HTML form in init.html:

<form>
<input type="text" id="projectFilepath" size="40" placeholder="Spot your project files">
<input type="button" id="spotButton" value="Spot">
</form>

How can I pass the user input from "projectFilepath" when a user clicks "spotButton" on a variable in my python script?

I'm new in Python and Flask, so forgive me if I make any mistakes.


Answer

The form tag needs some attributes set:

  1. action: The URL that the form data is sent to on submit. Generate it with url_for. It can be omitted if the same URL handles showing the form and processing the data.
  2. method="post": Submits the data as form data with the POST method. If not given, or explicitly set to get, the data is submitted in the query string (request.args) with the GET method instead.
  3. enctype="multipart/form-data": When the form contains file inputs, it must have this encoding set, otherwise the files will not be uploaded and Flask won't see them.

The input tag needs a name parameter.

Add a view to handle the submitted data, which is in request.form under the same key as the input's name. Any file inputs will be in request.files.

@app.route('/handle_data', methods=['POST'])
def handle_data():
    projectpath = request.form['projectFilepath']
    # your code
    # return a response

Set the form's action to that view's URL using url_for:

<form action="{{ url_for('handle_data') }}" method="post">
    <input type="text" name="projectFilepath">
    <input type="submit">
</form>